What is the easiest way to balance chemical equations?

Ok,I don't know why but I find in Chemistry that balancing equations is not a strong point!Can someone help me find an easy way to balance equations?|||Balancing is making sure there are equal numbers of each species on each side. There's actually a really simple way to do this. Just by balancing the species in the following order:





1. Metals


2. Non-metals


3. Unchanged polyatomic ions (ie. if it is sufate on the left and sulfate on the right)


4. Oxygen


5. Hydrogen





The reason hydrogen is last is that in many reactions hydrogen gas is evolved.





The exception is combustion reactions, where oxygen combines with something. In this case oxygen is balanced last (we can easily balance something that is on its own)





If you follow these rules, you can balance every equation|||the easiest way to balance them, is to first become familiar with the symbols of each of the elements, then; when in a chemical equation count the number of moles of each element, some may be diatomic ok its no problem honestly practice makes perfect just keep trying and trying and counting how many there are on each side, ull do great. smart gurl ;-)|||leave the Oxygens till the end and voila!!!!|||i always found that if you wrote down the number of each molecule on each side before hand it helps eg





NaOH + H2SO4 =%26gt; Na2SO4 + H2O





Firsat count the numbers on the left





Na - 1


O-5


H-3


S- 1





Then on the right





Na - 2


O - 5


H - 2


S - 1





then just balance it out|||When I do it I look for the element with the highest number of atoms first, change the other side so the numbers match. Then check the second highest all the way down. If the number of one of the other elements don't match the double the values until they do.





e.g





Al(s) + NaOH(aq) 鈫?H2(g) + Na3AlO3(aq)





Start with Na 3 on the right so make it 3NaOH to give the three Na s, the O then matches too but you have 3H on left and only 2 on the right. So double up to give 6NaOH you then have 2Na3AlO3 and 3H2. Double the Al on the left and it's balanced.





2Al + 3NaOH ---%26gt; 3H2 + 2Na3AlO3|||Start with the most complex molecule first, sometimes a carbon or a metal. Then just go from there, being sure to multiply each side when the atoms of one element increase. Remember that when an odd number exists on one side, you can multiply the other side by that number divided by two, and then multiply the whole equation of coefficients by two. This is the way to balance O2 with H2O.|||Leave the O and H to the end.|||There's only one way to make balancing equations easier....PRACTICE